10x^2+26x=79

Solution for 10x^2+26x=79 equation:

10x^2+26x=79

We move all terms to the left:

10x^2+26x-(79)=0

a = 10; b = 26; c = -79;
Δ = b2-4ac
Δ = 262-4·10·(-79)
Δ = 3836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3836}=\sqrt{4*959}=\sqrt{4}*\sqrt{959}=2\sqrt{959}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(26)-2\sqrt{959}}{2*10}=\frac{-26-2\sqrt{959}}{20}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(26)+2\sqrt{959}}{2*10}=\frac{-26+2\sqrt{959}}{20}
$